Solving Power Output for 3400 KG Truck on 8° Incline

  • Thread starter Thread starter AZhang
  • Start date Start date
  • Tags Tags
    Power
AI Thread Summary
To determine the power output required for a 3400 KG truck ascending an 8° incline at a constant velocity of 20 m/s, the resistive forces of 1200 N must be considered. The relevant formulas for power are Work/Time and Total Energy/Time. By selecting a time frame, such as one second, the distance traveled along the incline can be calculated, along with the vertical height gained. This information allows for the calculation of energy used to overcome friction and to elevate the truck. Ultimately, the power output can be found using the formula P = energy/time.
AZhang
Messages
13
Reaction score
0
A 3400 KG truck is driving up a road inclined at 8 degrees above the horizontal. If the resistive forces such as air drag and friction that act on the car add up to 1200 N, determine the power output necessary to keep the velocity constant at 20 m/s.

I don't really get how to set up my equations. Can someone help me?
 
Physics news on Phys.org
Have you got a formula for finding power? If not, try wikipedia.
 
I do, it's both Work/Time and Total Energy/Time, but I don't know how to use them in this scenario.
 
You need pick a convenient time OR distance to work with. Say you choose 1 second for the time. Then you must work out the distance along the incline that it goes in that time. And the height straight up that it goes. These numbers should allow you to calculate the energy used to overcome friction and the energy used to increase the height. Finally, P = energy/time should do the trick.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

How Do You Calculate Race Car Acceleration and Power Output?
Replies
20
Views
2K
Power used to move a car up an incline with friction
Replies
7
Views
6K
MHB Work energy principle and power
Replies
4
Views
1K
How Do You Calculate Engine Power for Semi Trucks in Various Conditions?
Replies
8
Views
3K
IB Physics Mechanics help? : Bus on an incline
Replies
7
Views
5K
Finding Frictional Force and Power Using Work and Energy
Replies
4
Views
3K
I A problem regarding power output in cycling
Replies
7
Views
1K
Torque Plus Power In Relation to Velocity
Replies
15
Views
2K
Calculating Tension in an Inclined Plane Problem
Replies
2
Views
2K
Cars Collide on a Hill, Conservation of Momentum
Replies
7
Views
2K

Hot Threads

Recent Insights

Back
Top