Solving Problem with Units: Max Elastic Potential Energy

[jg370]

Homework Statement

In a problem to determine the maximum elastic potential energy of a molecule, I have the following equation:

$$A= \sqrt{\frac{6.626*10^-34 Js}{2\pi}}\times(\frac{1}{(1.14*10^-26kg)(1.85*10^3N/m})^(1/4)$$

Homework Equations

The Attempt at a Solution

The answer is $$4.79*10^-12 m$$

I have tried to coax the definition of the Joule and Newton units to come out with an answer in meter; however I do not see how this can be made to work.

Thank you for your kind assistance

jg370

 

[LowlyPion]

(J*s)^1/2 = kg^1/2*m*s^-1/2

(N/m)^-1/4 = kg^-1/4*m^-1/4*s^1/2*m^1/4

And there hiding in the denominator - the extra kg^-1/4

As they say in poker "Pot's right."