Solving problems usng conservation of energy

AI Thread Summary
A block of mass 1.5 kg is released from a compressed spring and travels 0.9 m on a surface with a coefficient of kinetic friction of 0.4, achieving a velocity of 14.5 m/s. The conservation of energy principle is applied to relate the initial elastic potential energy of the spring to the kinetic energy of the block and the work done against friction. The calculations yield a spring constant k of approximately 321 N/m. There is a request for verification of the calculations, indicating a potential discrepancy in the numbers used. The discussion emphasizes the importance of accurate calculations in applying energy conservation principles.
tutojean
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Homework Statement


A block of mass 1.5 kg is placed against a horizontal spring of force constant k that is compressed .20 m. the spring is then released and the block travels to the right along a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.4. After the block has traveled 0.9 m to the right, measured from its initial position against the compressed spring, its velocity is 14.5 m/s. Calculate the force constant k of the spring.


Homework Equations


Kinetic/gravitational/elastic/friciton (Usage varies for different situations.


The Attempt at a Solution



[0+0+Es] Initial = [K+0+0+Ef]

1/2kv^(2) = 1/2mv^(2) = uNd

N=fg=mg so this replaces N essentially!

plugging in...

1/2k(0)^(2) = 1/2(1.5)(14.5)^(2) + (.4)(1.5)(9.8)(.9)

k=320.667
k=321 Nt

Is this correct? Just needing full proof assistance thank you so much.
 
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The method is correct but you need to redo the numbers because they don't agree with mine. What number did you put here (in red)?
tutojean said:
1/2k(0)^(2) = 1/2(1.5)(14.5)^(2) + (.4)(1.5)(9.8)(.9)

k=320.667
k=321 Nt
 
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