How Do You Find Volume Using PV=nRT?

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    Pv=nrt Volume
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To find volume using the ideal gas law PV=nRT, the discussion centers on the values for pressure (P), number of moles (n), the gas constant (R), and temperature (T). The user initially calculated volume using pressure in Pascals but later switched to atmospheres, leading to confusion over the correct volume. The correct calculation with R expressed in liter-atm/mol K yields a significantly large volume of approximately 118.64 liters for 5.3 moles of gas at standard temperature and pressure. Participants emphasize the importance of unit consistency throughout the calculations. The final volume indicates the substantial size required to contain the specified amount of gas.
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Homework Statement


upload_2015-5-15_0-53-46.png


Homework Equations


PV = nRT

The Attempt at a Solution


n = 5.3 moles
R = 8.31 J/(mol K)
T = 273 K
now, with P, do we use 1 atm or 1.013 x 105

i'll go with the latter, and the answer comes out to be 0.119 liters , does this sound correct?
 
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goonking said:

Homework Statement


View attachment 83502

Homework Equations


PV = nRT

The Attempt at a Solution


n = 5.3 moles
R = 8.31 J/(mol K)
T = 273 K
now, with P, do we use 1 atm or 1.013 x 105

i'll go with the latter, and the answer comes out to be 0.119 liters , does this sound correct?
What is R in terms of liter-atm/mol K ?
 
Raghav Gupta said:
What is R in terms of liter-atm/mol K ?
hmm, it is 0.082

also, do we normally express P in Pascals or atm?
 
goonking said:
hmm, it is 0.082

also, do we normally express P in Pascals or atm?
In SI units it is Pa but normally it is a very small unit.
In our day to day life we use atm.
Remember if you are solving you should keep a track on units.
Your attempt is also good.
You will get answer in m3 and then 1m3 = 1000 liter.
 
Raghav Gupta said:
In SI units it is Pa but normally it is a very small unit.
In our day to day life we use atm.
Remember if you are solving you should keep a track on units.
Your attempt is also good.
You will get answer in m3 and then 1m3 = 1000 liter.
hmmm, is 1.19 L correct?
 
goonking said:
hmmm, is 1.19 L correct?
No, can you show what have you done?
 
Raghav Gupta said:
No, can you show what have you done?

P V = n R T
(1.013x105) V = (5.3 moles )( 0.082 liter-atm/mol K) (273K)

V = 0.00119 , I'm pretty sure this is in liters
 
goonking said:
P V = n R T
(1.013x105) V = (5.3 moles )( 0.082 liter-atm/mol K) (273K)

V = 0.00119 , I'm pretty sure this is in liters
But P should be in atm then.
I said keep track of units.
So take P = 1atm.
 
Raghav Gupta said:
But P should be in atm then.
I said keep track of units.
So take P = 1atm.
so V = (5.3 moles )( 0.082 liter-atm/mol K) (273K) = 118.64 Liters?

thats huge for a bottle
 
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goonking said:
so V = (5.3 moles )( 0.082 liter-atm/mol K) (273K) = 118.64 Liters?

thats huge for a bottle
Yeah, that was what I was getting.

Yeah, that is huge for a bottle but holding 5.3 moles of an ideal gas is a big thing.
 
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