Solving Redox Equations: Cathodic Reaction of Oxygen

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The discussion focuses on identifying the correct half-equation for the cathodic reaction of oxygen in redox equations. Two potential equations are presented: one from lecture notes, O2 + 2H2O + 4e^- -> 4OH^-, and another proposed by the user, O2 + 4H^+ + 4e^- -> 2H2O. Both equations are valid and represent different conditions under which the reaction may occur. The need for additional context, such as reaction conditions and potentials, is emphasized to determine the appropriate equation. Understanding the specific environment is crucial for selecting the correct half-equation for the cathodic reaction of oxygen.
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Homework Statement


Write the half equation for the cathodic reaction of oxygen

The Attempt at a Solution


Now I know that the cathodic reaction will be reduction and so the oxygen will be gaining electrons. I thought I had the answer from the lecture notes, but then I thought of another possible equation that would work too and I don't know which one is right??

The two equations are as follows:
equation from notes( the notes say that this is the most common)
O_2 + 2H_2O + 4e^- ->4OH^-

the equation I came up with
O_2 + 4H^+ + 4e^- ->2H_2O

Are these just two possible half equations for the cathodic reaction of oxygen or is one wrong??

Thanks for your time
 
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I think we need more context here. Both reactions are legal, and likely occur at quite different potentials, so additional details are necessary.
 
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