Solving Satellite Orbits: Geostationary Radius & Speed

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The discussion focuses on solving a physics problem related to a geostationary satellite. The radius of the geostationary orbit is calculated using Kepler's Third Law, resulting in approximately 42,200 kilometers. The linear speed of the satellite is determined to be about 3.07 kilometers per second. The calculations involve applying formulas for centripetal acceleration and orbital motion. This information provides a clear understanding of the satellite's orbital dynamics.
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Hi People I had problems solvin this question could you please help me,

The question:

On 19th June 1981,an experimental meteorological satellite of mass m=700 kg,was placed in a geostationary orbit usingthe launch vehicle Ariane.

Calculate:

a) the radius of geostationary orbit given that the period of revolution of the satellite is 23 h 56 m

b)the linear speed of such a satellite
 
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Treat the orbit as an example of circular motion. What's the force pulling the satellite in a circle? Apply what you should know about centripetal acceleration.

Show your work if you need more help.
 
in its orbit

Hi there,

I'd be happy to help you with this question. Let's break it down step by step.

a) To calculate the radius of a geostationary orbit, we can use Kepler's Third Law: T^2 = (4π^2/GM)*r^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the central body (Earth in this case), and r is the radius of the orbit. We can rearrange this equation to solve for r:

r = (GMT^2/4π^2)^(1/3)

Plugging in the values given in the question, we get:

r = [(6.67 x 10^-11 Nm^2/kg^2)(5.98 x 10^24 kg)(23 h 56 m)^2]/(4π^2)^(1/3)

= 4.22 x 10^7 meters

Therefore, the radius of the geostationary orbit is approximately 42,200 kilometers.

b) To calculate the linear speed of the satellite, we can use the formula v = 2πr/T, where v is the linear speed, r is the radius of the orbit, and T is the period of revolution. Plugging in the values from part a, we get:

v = (2π)(4.22 x 10^7 meters)/(23 h 56 m)

= 3.07 km/s

So the linear speed of the satellite in its geostationary orbit is approximately 3.07 kilometers per second.

I hope this helps! Let me know if you have any further questions or need clarification on any of the steps. Good luck!
 
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