Jeann25
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How would I start this one? I tried dividing by y, but that does not work
y'=xy/(1+x²)
y'=xy/(1+x²)
Jeann25 said:How would I start this one? I tried dividing by y, but that does not work
y'=xy/(1+x²)
Jeann25 said:Here's what I did:
1/y y' = x/(1+x²)
ln y = 1/2 ln (1+x²)+c
y = ce^(1/2 ln(1+x²))
Answer's supposed to be: c*sqrt(1+x²)