Solving Separable DE with Initial Value: Techniques and Examples

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How would I start this one? I tried dividing by y, but that does not work

y'=xy/(1+x²)
 
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Why doesn't that work?
 
Jeann25 said:
How would I start this one? I tried dividing by y, but that does not work

y'=xy/(1+x²)

Yeah why does dividing by y not work?
 
Here's what I did:

1/y y' = x/(1+x²)
ln y = 1/2 ln (1+x²)+c
y = ce^(1/2 ln(1+x²))

Answer's supposed to be: c*sqrt(1+x²)
 
Jeann25 said:
Here's what I did:

1/y y' = x/(1+x²)
ln y = 1/2 ln (1+x²)+c
y = ce^(1/2 ln(1+x²))

Answer's supposed to be: c*sqrt(1+x²)

Yeah, ok and how is that different from what you had? Just simplify your expression with the properties of logs.
 
Nevermind. I get it now. Thank you :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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