Solving Series RLC Circuit: Vrms Across Capacitor & Inductor is Zero

AI Thread Summary
To achieve zero Vrms across the capacitor and inductor in a series RLC circuit, the resonant condition must be met, where the inductive reactance equals the capacitive reactance (XL = XC). Given the power source frequency of ω = 500 rad/s, the resonance frequency equation ω² = 1/LC can be used to solve for the required capacitance. Substituting L = 0.1 H into the equation yields a capacitance of 0.00004 F. The discussion emphasizes understanding the phase relationship between the voltages across the inductor and capacitor, which is crucial for resonance. This analysis clarifies the conditions necessary for achieving resonance in the circuit.
reddawg
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Homework Statement


Given a series RLC circuit:

R = 10 Ω
L = 0.1 H
C = 2 μF
Power Source: V = 5sin(500t)

If you could change the capacitance what C would you select so Vrms across the capacitor and inductor is zero?

Homework Equations


ω2 = 1/LC

The Attempt at a Solution


My instructor's solutions say to use above equation for resonance frequency to input ω=500 (given from V) and
L = 0.1 H and then solve for C, yielding 0.00004 F.

This makes no sense, could someone explain it to me?
 
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reddawg said:
This makes no sense, could someone explain it to me?
Remember: The voltage across the inductance is 180° out of phase with respect to the voltage across the capacitor (jωL vs. 1/[jωC]).
 
Svein said:
Remember: The voltage across the inductance is 180° out of phase with respect to the voltage across the capacitor (jωL vs. 1/[jωC]).
Ok, I think I get it.

Given a phaser representation, tan(φ) = (XL - XC) / R

So tan(180) = 0 ⇒ XL = XC which is resonance.
 
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