Solving Simple Work Problem: 515J

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The sailor's work calculation involves climbing an 11.5 m rope ladder at a 30° angle, with a mass of 70.0 kg. The initial calculation yielded 515 J using the formula W = -mgd sin(θ), but this was deemed incorrect. The error lies in the interpretation of the angle; the angle should be considered with respect to the vertical rather than the horizontal. Correcting the angle will lead to the accurate calculation of work done by the sailor.
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Homework Statement


A 70.0 kg sailor climbs an 11.5 m long rope ladder to a mast above at constant velocity. The rope ladder is at an angle of 30.0° with the mast. Assume that the ladder is frictionless. How much work does the sailor do?

Homework Equations


##W = Fd##

The Attempt at a Solution


[/B]
##F_{net||} = F_{a} + F_{g||}##
##F_{a} = -F_{g} = -mg\sin \theta##
##W = F_{a}d##
##W = -mgd\sin \theta##
##W = -(70kg)(-9.8m/s^{2})(11.5m)0.5##
##W = 515 J##

However, in the solution manual, this is not the correct answer. What am I doing wrong?
 
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Mr Davis 97 said:

Homework Statement


A 70.0 kg sailor climbs an 11.5 m long rope ladder to a mast above at constant velocity. The rope ladder is at an angle of 30.0° with the mast. Assume that the ladder is frictionless. How much work does the sailor do?

Homework Equations


##W = Fd##

The Attempt at a Solution


[/B]
##F_{net||} = F_{a} + F_{g||}##
##F_{a} = -F_{g} = -mg\sin \theta##
##W = F_{a}d##
##W = -mgd\sin \theta##
##W = -(70kg)(-9.8m/s^{2})(11.5m)0.5##
##W = 515 J##

However, in the solution manual, this is not the correct answer. What am I doing wrong?
The angle, θ, that you used is with respect to the deck, so it's not 30° .

That is to say, if you use sin(θ) that is with respect to the deck.
 
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