Solving Summation Question: Alternating Series Test

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Homework Help Overview

The discussion revolves around a summation problem involving an alternating series defined by the expression \(\sum _{p=0} ^{\infty} (-1)^p \frac{4p+1}{4^p}\). Participants are exploring convergence properties and potential methods for finding the sum of the series.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the Alternating Series Test to determine convergence, questioning the validity of their reasoning and the numerical value of the sum. Other participants engage by confirming convergence but challenge the assertion of a specific sum value, prompting further inquiry into subsequent steps for evaluation.

Discussion Status

Participants are actively discussing the convergence of the series and the implications of the Alternating Series Test. There is recognition of conditional convergence, but no consensus on the numerical value of the sum. The conversation is ongoing, with participants suggesting further methods and questioning assumptions.

Contextual Notes

There is a mention of a previous thread where methods were suggested, indicating a continuity in the discussion. Participants are also considering the implications of the series' convergence in relation to the terms involved.

Hummingbird25
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HELP: A summation question

Hi

Given the sum

[tex]\sum _{p=0} ^{\infty} (-1)^p \frac{4p+1}{4^p}[/tex]

I have tried something please tell if I'm on the right track

Looking at the alternating series test

(a) [tex]1/(4^{p+1}) < (1/(4^p))[/tex]

(b) [tex]\mathop {\lim }\limits_{p \to \infty } b_p = \mathop {\lim }\limits_{p \to \infty } \frac{1}{{4^p }} = 0[/tex]


Then according to the test this allows me to write [tex]\sum _{p = 0} ^{\infty} 4^{-p} = 4/3[/tex]

Can anybody please verify if I'm heading in the right direction on this? Or am I totally wrong?

Sincerely Yours

Hummingbird
 
Last edited:
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I agree that you've shown this series converges, but I don't see where you're getting that you can say it converges to [itex]\frac{4}{3}[/itex]. The Alternating Series Test can show conditional convergence, but not a numerical value to the best of my knowledge.
 
Okay thanks I can see that now,

but what would be the next logical step to find the sum of this series? Should I use a specific test?

Sincerely Yours
Hummingbird25

p.s. Since it converges, then |1/(4^p)| < 1 ??

Jameson said:
I agree that you've shown this series converges, but I don't see where you're getting that you can say it converges to [itex]\frac{4}{3}[/itex]. The Alternating Series Test can show conditional convergence, but not a numerical value to the best of my knowledge.
 
Last edited:
Hummingbird25 said:
but what would be the next logical step to find the sum of this series? Should I use a specific test?

This is another of those that can be broken up with one of the summands being of the form [tex]px^p[/tex]. Remember the method I suggested in your other thread ?
 
Hello and the other sum being

(-1)^p ?

Sincerely Hummingbird25

Curious3141 said:
This is another of those that can be broken up with one of the summands being of the form [tex]px^p[/tex]. Remember the method I suggested in your other thread ?
 
Hummingbird25 said:
Hello and the other sum being

(-1)^p ?

Sincerely Hummingbird25

No, the other summand is [tex](-4)^{-p}[/tex].

That's just a geometric series.
 

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