Solving Tension in a Chain of 5 Links

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To solve the problem of a chain with five links being lifted with a constant acceleration of 2.5 m/s², the forces acting between adjacent links must be calculated first. The weight of each link is 0.10 kg multiplied by the acceleration due to gravity, which contributes to the tension in the chain. The resultant force on the fifth link is determined by the force exerted by the fourth link minus its weight. Finally, the force exerted in the top link can be found by considering the total weight of the chain and the acceleration. Understanding these forces is crucial for accurately determining the tension throughout the chain.
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Homework Statement


A chain consisting of five links, each of mass 0.10 kg, is lifted vertically with a constant acceleration of 2.5m/s^2.
a.) Find the forces acting between adjacent links.
b.) Find the force F exerted in the top link.



Homework Equations


F=ma
W=mg


The Attempt at a Solution


I am just having trouble knowing where to start with this problem. I'm guessing that the top link should be determined last since it is in part b. Any input would be greatly appreciated. Thank You!
 
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Since there is an acceleration, there will be a resultant force.

At the fifth link,
The resultant force = force exerted by fourth link on fifth link - weight of fifth link.

I think you should be able to do now.
 
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