Solving Tension & Pulley Homework Problem

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    Pulley Tension
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The discussion centers on solving a tension and pulley problem in physics, emphasizing the balance of forces in a system with pulleys. Participants clarify that the tension in the rope remains constant if the pulleys are assumed frictionless. The conversation highlights the importance of considering multiple ropes and their contributions to the overall tension, leading to a total tension of 2T on one side due to two segments of the rope. A participant successfully resolves their confusion regarding the forces after receiving clarification on the mechanics involved. The discussion ultimately reinforces the principle that the weight of the mass interacts with the total tension in the system, regardless of the rope's uniformity.
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Homework Statement


See figure.


Homework Equations


\sum F_{y} = 0
\sum F_{x} = 0


The Attempt at a Solution



I can't see how to solve this. The only thing I can think of is the vertical forces of both sides of the pulley are going to equal the gravitational force of the mass in and that the two x components on each side of the rope will cancel.

I don't have the magnitude on the right hand side of the pulley and on the left hand side I don't have the magnitude or the angle. How do we solve this?

Thanks in advance.
 

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Hi jegues! :smile:

The question doesn't say that the pulleys are frictionless, but I think you'd better assume they are.

If so, then the tension T will be the same all the way along the rope. :wink:
 
If the tension is constant across the pulley, then isn't it just like ignoring the pulley and pulling on the rope directly?

See my FBD to get what I'm trying to say.
 

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Hi jegues! :smile:

No, because there's three arrows, one up-left, and two up-right, all with magnitude T. :wink:
 
because there's three arrows, one up-left, and two up-right, all with magnitude T

Thank you tiny-tim, with that I was able to solve it.

But for a conceptual clarification of why there is two up-right, is it because of the 2nd pulley the cord passes over?

Thanks again!
 
No, it's because there's two ropes on the right …

you have to add the tensions (they happen to be the same, but if they weren't, you'd still add them)
 
But it's the same rope passing over the pulley, the tension should remain constant so why isn't it simply T instead of 2T?
 
The weight doesn't know they're the same rope. :wink:
 

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