Solving the Equation (y^2)+(y')^2=1: Ideas and Guidance

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Homework Statement



Find a function of y whose square plus the square of its derivative is 1.
i.e. (y^2)+(y')^2=1 and carry out your ideas.


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The Attempt at a Solution



Can anyone just help me out with this one. Kinda confused by the questioning. Just point me in the right direction.
 
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Think trig identities...
 
I still don't see it. How does the derivative factor into it?
 
Dr. Lady is suggesting you simply guess the answer.
Otherwise you have y'=+/-sqrt(1-y^2). You can try to integrate that.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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