Solving the Mystery of Calculating 10ul and 0.25ml for Protocol Steps

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The discussion revolves around a protocol involving chloroplast solutions, specifically the addition of proteinase K and SDS to achieve desired concentrations. The initial query focuses on how to calculate the addition of 10 µl of proteinase K to achieve a final concentration of 50 µg/ml, given the uncertainty about the total volume after adding the enzyme. Clarifications indicate that 10 µl of proteinase K at 20 mg/ml results in 200 µg, which, when diluted in 4 ml, gives the required concentration. Further confusion arises regarding the addition of SDS to achieve a final concentration of 0.5%. Participants explain that the percentage concentration can be interpreted as weight per volume, equating to grams per 100 ml, which simplifies calculations. This clarification helps in understanding how to derive the necessary volumes of SDS solutions (10% and 20%) to reach the desired concentration. The conversation emphasizes the importance of understanding concentration calculations and the interpretation of percentage solutions in laboratory protocols.
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here is a part of the protocol we did:

a)spin down the chloroplast solution and decant the supernatant. add 4ml water to the pellet.

b) add 10ul proteinase K ( concentration= 20mg/ml) to get a final concentration of 50ug/ml.

-> how do they get 10ul? which formula do they use? i don't think that they use the dilution formula (C1 XV1= C2 X V2) since we don't know the total volume of the solution. it can't be 4ml, because when we add proteinase K the volume of the solution will increase.


c) then add slowly 0.25ml 10% or 0.125ml 20% SDS to get a final concentration of 0.5% SDS.

-> again, how do they come to 0.25ml 10% or 0.125ml 20% SDS to get a final concentration of 0.5% SDS?


i am very stucked, please help!
 
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Hello

Please remember that some protocols do not reveal some data in order to maintain full usage. Your approach is a logical one, so I conclude that there is something not disclosed.

10 microliters of proteinase K with a concentration of 20 mg/mL makes 10 micrograms of enzyme solution. I am sure you are aware of this. If you calculate the overall concentration, you may find the same result.

With the same way, they probably calculated the overall concentration of SDS in the final solution and required that you provide the same.

Regards
chem_tr
 
thank, you so much for helping me out! but i am still very confused, so i hope you will keep helping me out.

i have found the answer for a)

X/10ul=20ug/ul
X= 200ug

200ug/4ml= 50ug/ml.

this is what they get.

but, i can't figure out the answer of b) since the unit is in percent.


i am so confused so i really hope for replies!
thank you so much again!
 
The formula for percentage is the same you used for calculating the correct concentration of proteinase K. An easier to see it, the % represent Weight per volume. So you had 10 g of SDS into 100 mL of water so 10%=[1g/10mL]
 
Just to add a clarification to iansmith's post: A weight/volume solution expressed as a percentage can also be read to have units of g/100ml. It means exactly the same thing. Using g/100 ml in your calculations makes it far easier to balance your units and make sure your math is correct.
 
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