Solving the Speed of a Projectile Passes an Observation Satellite

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AI Thread Summary
The discussion revolves around calculating the speed of a projectile as it passes an observation satellite orbiting an airless planet. Participants clarify the use of kinetic and potential energy equations, emphasizing the need to account for both the initial and final states of energy. There is confusion regarding whether to include the mass of the satellite in calculations, with consensus that the mass of the projectile cancels out. The importance of correctly applying gravitational potential energy formulas is highlighted, particularly the need to consider the satellite's orbital motion. The thread concludes with a request for clearer calculations to identify any potential errors in the approach.
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Homework Statement


A huge cannon is assembled on an airless planet. The planet has a radius of 6.00×106 m and a mass of 3.06×1024 kg. The cannon fires a projectile straight up at 5270 m/s.
An observation satellite orbits the planet at a height of 4103.30 km. What is the projectile�s speed as it passes the satellite?


Homework Equations


K=mv^2/2
U=-GMm/r



The Attempt at a Solution


Initially: Ki and Ui are both present
Finally: Ki and Uf are both present again
CORRECT?
so i have the equation
Ki-Ui=Kf-Uf
wanting to solve for velocity at a certain point Uf actually is GMm/(R+H)
CORRECT?
So then I solved for Vf and get ...
squareroot (2(Ki-Ui+Uf)/m)

Then i plug and go...WHY ISN'T WORKING
 
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You seem to have the basic idea.

Kinetic energy at firing + potential energy gravity at surface = potential energy at satellite + kinetic energy of projectile.
 
after plugging in the KE and PE equations i came up with...-2(-.5Vi^2+GM/R-GM/(R+h))
square root of the whole thing.
 
so instead of using the mass of the planet i should use mass of the sataellite?

EDIT: I don't have the mass of the satellite so I believe I have it set up right.
 
talaroue said:
so instead of using the mass of the planet i should use mass of the sataellite?

No. Of course not.

The Mass of the Planet and G give you a way to figure your potential energy ...

U = -GM/r

So ...

at surface U = the above.
at the satellite U = -GM/(r+h)

(Don't forget the sign.)
 
wanting to solve for velocity at a certain point Uf actually is GMm/(R+H)

So then the way I set it up is right?
 
talaroue said:
So then the way I set it up is right?

So long as you have also accounted for the potential energy at the surface as well.
 
You forgot that the satellite is in orbit. It's moving, too.
 
I attached my equation.
 

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  • #10
D H said:
You forgot that the satellite is in orbit. It's moving, too.

you can't just assume it isn't moving?
 
  • #11
I don't think they are asking for the speed relative to the satellite.

Merely the speed at the height (radius) of the satellite's orbit.
 
  • #12
thats what I figured. I figured that they just wanted the distance. Is my equation correct that i attached a few posts back?
 
  • #13
talaroue said:
thats what I figured. I figured that they just wanted the distance. Is my equation correct that i attached a few posts back?

Looks like the - in front of the 2 is not useful.

I would examine they way you treated the mass of the projectile ... as a suggestion.
 
  • #14
The mass should cancel. i meant to erase it, and the 2 shouldn't be negative. I just worked through that equation and it said the answer is wrong.
 
Last edited:
  • #15
talaroue said:
It cancels.

Not in the equation you supplied.
 
  • #16
Opps that is my bad, I knew it canceled in my mind but when I re wrote it i forgot to cancel it even though I canceled the others.

EDIT: WHen i worked through it, i didn't use the negative or the mass and it was wrong
 
  • #17
Has this question been resolved?
 
  • #18
talaroue said:
Opps that is my bad, I knew it canceled in my mind but when I re wrote it i forgot to cancel it even though I canceled the others.

EDIT: WHen i worked through it, i didn't use the negative or the mass and it was wrong

Maybe show your work? Perhaps you have a simple error?
 
  • #19
Wouldn't it just be easier to use S(t)=-gt^{2}+V_{o}t+h_{o}?
 
  • #20
No. That equation assumes a uniform gravity field.
 
  • #21
hmmmm i was never able to get it.
 
  • #22
talaroue said:
hmmmm i was never able to get it.

Maybe show your actual calculation?
 
  • #23
ok ill try to get that on here hold on.
 
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