Solving the Stopping Force of an Arrow Shot into Hay

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An arrow with a mass of 20 grams is shot into hay at 60 m/s and penetrates 20 cm before stopping. The average stopping force acting on the arrow was initially calculated incorrectly as 360 N. Upon reevaluation, the correct average stopping force is determined to be 180 N. The mistake was attributed to misinterpreting the work done by the stopping force, highlighting the simplicity of applying Newton's second law (F = ma) instead. This discussion emphasizes the importance of careful reading and understanding of physics problems.
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An arrow of mass 20 grams is shot horizontally into a bale of hay with a velocity of 60 m/s. It penetrates a debpt of 20 CM before stopping.

What is the average stopping force acting on the arrow?


I've been doing

W = -F*D
W = -(ma)*d

I'm finding a by using a kinematic equation, v (final ) ^2 = v (initial ) ^ 2 + 2 a (delta) x.

The answer I'm getting is 360 N, but that is not the correct answer. Any ideas?
 
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I'm an idiot. Never mind. I misread to work done by the stopping force. 180 is the right answer for those that care. There is no need for work at all, just a simple F = ma problem.
 
If misreading the question makes one an idiot, I'm an idiot many times over for trasngressions as an undergrad :(
 
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