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missteresadee

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dP/dt=(B_o)e^(-at)P

Solve this differential equation exactly. Suppose the initially at t=0, there are 10^6 tumor cells, and that P(t) is then increase at a rate of 3*10^5 cells per month. After 6 months, the tumor has double in population. Find a, and find the behavior of the tumor population as t goes to infinity

I know from the given information, I can find B_0 by using this equation

3*10^5=(B_0)*e^(-a*0)*10^6

given rate of change is 3*10^5; t=0, and p=10^6

B_0=3/10

I am having trouble finding my constant C, a...