Solving this exercise in mechanics -- Tipping over this rectangular object

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Discussion Overview

The discussion revolves around the mechanics of a rectangular object placed on a surface with friction, specifically focusing on the conditions that would cause the object to tip over when a force is applied at its upper end. The conversation explores theoretical aspects of friction, torque, and the geometry of the object.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants propose that the body will slide if the frictional force is less than the applied force, questioning the role of friction in the tipping condition.
  • Others argue that the position of the applied force, particularly being at the top rather than through the center of gravity, is crucial in determining whether the body will tip.
  • A participant notes that the corner radius may not matter unless specific geometric conditions are met, such as when the width equals the height.
  • There is a suggestion to sum the torques about the tipping point and consider the coefficient of friction, as the pushing force could slip before the object tips.
  • One participant challenges another to provide an equation to clarify their reasoning, emphasizing the need for a mathematical approach to the problem.
  • Another participant suggests calculating the torques due to both the mass and the friction to determine the total rotational force and whether the object will rotate.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of the corner radius and the conditions under which the object will tip. The discussion remains unresolved, with multiple competing perspectives on the mechanics involved.

Contextual Notes

There are limitations regarding unspecified parameters such as the coefficient of friction and the corner radius, which may affect the analysis. The discussion also highlights the need for clarity in the assumptions made about the object's geometry and the forces acting on it.

yam1244
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Moved from a technical forum, so homework template missing
A body is placed on a surface with friction
Force is applied to the right at the upper end of the body
What is the condition that will cause the body to roll over?

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Welcome to PF.

The block will simply slide if the frictional force is less than the applied force.
What is the frictional force?
Does it matter that the corners are rounded?
Is this homework ?
 
It is not homework.
Frictional force is parameters.
Corner not matter.

As for your answer, I thought so too, but note that the position of the force is at the top of the section (rather than passing through the center of gravity), which means that you imagine that the body was a very narrow, high rectangle.
 
yam1244 said:
Corner not matter.
Unless W = H and corner radius = h/2.
There must be additional constraints on the problem, or required in the answer.
 
What constraint is missing?
The problem I presented is not a test exercise, it is a conceptual problem to understand if and how the friction affects the body's overturning.
You wrote earlier that when the frictional force is greater the body will turn over, but I do not see the effect of the position of force on the body.
Try to write an equation.
 
yam1244 said:
Try to write an equation.
Sum the torques about the tipping point. You will also need the coefficient of friction between the pushing object and the monolith, since the pushing force could slip before the object tips.
 
yam1244 said:
Try to write an equation.
You asked the question, so you should show your attempt to write an equation.
yam1244 said:
Corner not matter.
@yam1244
What happens when; W = H; and r = H/2 ?
Do you need to include your unspecified corner radius in the equation ?
 
yam1244 said:
You wrote earlier that when the frictional force is greater the body will turn over, ...
Who wrote that earlier, and where was it written.
 
Calculate two rotational forces:
1) The torque due to the mass at a distance from the lower right corner.
2) The torque due to the friction on the lower right corner and the opposing force applied to the upper left corner.
The total rotational force should tell you if it will rotate.
 

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