Solving Torque Questions: Mass, Distance & Speed

  • Thread starter Thread starter Power of One
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
To determine how many Earth years are in a Pluto year, the gravitational force between the Sun and Pluto can be equated to the centripetal force, allowing for the calculation of Pluto's orbital period. For the second problem, the walnut's horizontal distance can be analyzed using the equation x = x0 + vit - (1/2)gt^2, where x0 is the initial height. The time it takes for the walnut to fall can be derived from the vertical motion, while the horizontal distance relates to the bird's speed. Clarification on the gravitational force's role in calculating time was requested multiple times, indicating confusion around the relationship between vertical and horizontal motion. Understanding these principles is essential for solving both problems effectively.
Power of One
Messages
23
Reaction score
0

Homework Statement


1. Given the mass of Pluto and the sun, and the distance between the two, how would you find how many Earth years are in a Pluto year?

2. A bird flying over you drops a walnut. If the bird is flying horizontal at an altitude of 23.5m, and the walnut travels a horizontal distance of 12.5m, how fast was the bird flying.

Homework Equations


1. Centripetal force= mv^2/r?

2. x= vit +.5at^2?

The Attempt at a Solution



I have no idea where to start. Can someone please help lead me down the right path?
 
Physics news on Phys.org
Power of One said:
1. Given the mass of Pluto and the sun, and the distance between the two, how would you find how many Earth years are in a Pluto year?

The gravitational force between the Sun and Pluto provide the centripetal force needed to keep Pluto in orbit. Use this to get the time it takes Pluto to revolve around the Sun.


Power of One said:
2. A bird flying over you drops a walnut. If the bird is flying horizontal at an altitude of 23.5m, and the walnut travels a horizontal distance of 12.5m, how fast was the bird flying.
Yes you need to use 2. x=x0 vit -(1/2)gt2

Vertically speaking, what is the initial displacement x0? What is the horizontal range equal to in terms of time and velocity?
 
How does the gravitational force used to find the time?

I still don't understand number 2, can someone explain it again?
 
Power of One said:
How does the gravitational force used to find the time?

Equate the gravitational force to the centripetal force to find the periodic time T.

Power of One said:
I still don't understand number 2, can someone explain it again?

x=x0+vit -(1/2)gt2

x0 is the initial displacement. If the horizontal velocity is v, then what is the range R(=12.5m) equal to?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top