Solving trig function (possible error in solutions)

[sandy.bridge]

Homework Statement

Alright, so I am going through the solutions to one problem that has me stumped, and initial instinct tells me it is wrong, however, I figured I would get clarification.

The Attempt at a Solution

sin(2t)=cos(2t)
tan(2t)=1
2t=\pi{/}4, 5\pi{/}4

However, the book states both positive and negative values, rather than just positive. It's either not correct, or not clicking. tan(-π/4)=-1, not 1..

 

[I like Serena]

What is tan(-3pi/4)?

 

[dynamicsolo]

Since your text is suggesting that there are positive and negative solutions, you are not restricted to the "principal circle" , 0 ≤ t < 2{\pi} . So you can "go around the circle" as many times as you like:

2t = \frac{\pi}{4} + k \cdot 2{\pi} , \frac{5\pi}{4} + k \cdot 2{\pi} ,

with k being any integer.

 

[SammyS]

Homework Statement

Alright, so I am going through the solutions to one problem that has me stumped, and initial instinct tells me it is wrong, however, I figured I would get clarification.

The Attempt at a Solution

sin(2t)=cos(2t)
tan(2t)=1
2t=\pi{/}4, 5\pi{/}4

However, the book states both positive and negative values, rather than just positive. It's either not correct, or not clicking. tan(-π/4)=-1, not 1..

Are you sure the problem isn't, \sin^2(t)=\cos^2(t)\,?