Solving Trigonometry Equation Algebraically

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The discussion focuses on solving the trigonometric equation 2 sin²(x) - 5 sin(x) = 3 both graphically and algebraically. A graphical solution using a TI-83 calculator yielded intersection points at x = -5π/6, -π/6, 7π/6, and 11π/6 within the domain 0 ≤ x ≤ 2π. The user seeks assistance with the algebraic approach, considering potential substitutions to simplify the equation. A hint suggests factoring the equation into a product form to facilitate finding solutions. The thread emphasizes the importance of understanding the algebraic manipulation of trigonometric functions for accurate solutions.
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[SOLVED] trigonometry math 30pure

Homework Statement


a student is given the following sinusoidal

2 sin^2 (x)-5sinx=3

Homework Equations



1) Determine the solution to the equation , defined on the domain using a graphical approach over the domain 0 \leq x \leq 2 \pi. Give solutions as exact values.
2) Determine the solution to the equation , defined on the domain using a algebraic approach over the domain 0 \leq x \leq 2 \pi. Give solutions as exact values.


The Attempt at a Solution



1) using my grafic calculator TI-83 plus i find this answers

  • Equation: Y1= 2 sin^2 (x)-5sinx, Y2= 3
  • Window: zoom trig
  • I/Z= find intersection points.
  • Answer: x= (-5)(\pi)/6, (-1)(\pi)/6, (7)(\pi)/6, (11)(\pi)/6
2) now in this point i need help to do it algrbraticaly, i can't figure out how to do it or find any other example in my notes...
is it using the equation y= a Sin[b(x-c)]+d??
thanks
 
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note: oh it looks like where there is a pi as if it was n^pi but is not ...is actually N x pie ..(the pie is timing the number infront of it.)
 
note that x only exists in the sin function, so you may do an appropriate substitution do get a more comfortable equation.
 
Hi cathoderay! :smile:

(copy ² and π and anything else you like, for future use! … or, if you have a Mac, type alt-p for π. :smile:)

Forget your TI-83+, and go for the simple answer …

Hint: what is 2sin²x - 5sinx - 3 as a product (A sinx + B)(Csinx + D)? :smile:
 
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