Solving Vector Subspace Questions: A & B in V

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Hey guys this is the question

. Let A and B be vector subspaces of a vector space V .
The intersection of A and B, A ∩ B, is the set {x ∈ V | x ∈ A and x ∈ B}.
The union of A and B, A ∪ B, is the set {x ∈ V | x ∈ A or x ∈ B}.
a) Determine whether or not A ∩ B is a vector subspace of V . Prove your answer.
b) Determine whether or not A ∪ B is a vector subspace of V . Prove your answer.


My strategy for this is to find two subspaces in V and find a counter claim so that the union of A and B is not a subspace and similarly for the intersection of A and B would this be strategy be enough to answer the question?

thanks so much.
 
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for the union pick arbitrary elements a in A, b in B, is a+b in A U B?
 
for int pick arbitrary elements in A int B, and test the subspace closure requirements
 
flon said:
Hey guys this is the question

. Let A and B be vector subspaces of a vector space V .
The intersection of A and B, A ∩ B, is the set {x ∈ V | x ∈ A and x ∈ B}.
The union of A and B, A ∪ B, is the set {x ∈ V | x ∈ A or x ∈ B}.
a) Determine whether or not A ∩ B is a vector subspace of V . Prove your answer.
b) Determine whether or not A ∪ B is a vector subspace of V . Prove your answer.


My strategy for this is to find two subspaces in V and find a counter claim so that the union of A and B is not a subspace and similarly for the intersection of A and B would this be strategy be enough to answer the question?

thanks so much.
It would be sufficient if they are both not subspaces. But are you sure of that?
 
sorry if the intersection and union are both NOT subspaces?
 
yeah, you'll only find a counter example if they are not a subspace
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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