Solving Wave Equation with Paraxial Approximation

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If U_0(r,z)=V(r,z)e^{ikz}, then:

\frac{\partial U_0}{\partial z}=\frac{\partial V}{\partial z}e^{ikz}+ikVe^{ikz}

due to the product rule.

so... \frac{\partial^2 U_0}{\partial z^2}=\ldots? :wink:
 
Oops, I see now I was looking past the obvious. I'll do the calculation in the morning. Is there a reason why they leave out the e^{ikz} from the final equation?

Thanks.

edit: V = V(r,z)e^{ikz}?
 
Last edited:
Confundo said:
Oops, I see now I was looking past the obvious. I'll do the calculation in the morning. Is there a reason why they leave out the e^{ikz} from the final equation?

They haven't "left it out"...To see what becomes of that term, work out the derivatives in equation (4) using the assumed form of U_0.


edit: V = V(r,z)e^{ikz}?

Huh?! :confused:...What are you trying to ask here?
 
Worked that out now, must learn not to try and do derivatives in my head while tired.
 
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