Solving Work Done Problem: Minimize Work, Angle & Magnitude of Force

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To minimize work done in moving a block on a horizontal table, the optimal angle for the driving force is not 90 degrees, as that would result in zero work but fail to move the block. Instead, a slight angle just below 90 degrees is necessary to provide a minimal horizontal component of force while still overcoming friction. The discussion highlights confusion regarding the problem's requirements, suggesting that the question may not be well-structured for academic assessment. Participants express frustration over the ambiguity and complexity of the problem. Ultimately, a balance between minimizing work and achieving movement is essential.
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Homework Statement


There is a block of weight mg sitting on a horizontal table with a coefficient of kinetic friction u, at what angle to the horizontal should one direct a driving force to minimise work done in moving the block a horizontal distance of 10m with nonzero velocity and what is the magnitude of that work?

Homework Equations


W=integral(F.ds)
F=uR

The Attempt at a Solution


Looking at this problem I cannot see why it would not be 90degrees and zero work being done because the direction of motion would be perpendicular to the force so F.ds is 0. But this is a 7 mark question surely that explanation isn't worth 7 marks have I missed something?
Thank you
 
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sorax123 said:
Looking at this problem I cannot see why it would not be 90degrees and zero work being done because the direction of motion would be perpendicular to the force so F.ds is 0.
That would certainly minimize the work! But would that allow you to move the block as required?
 
Doc Al said:
That would certainly minimize the work! But would that allow you to move the block as required?
So would you say 89.999999999...?
 
On second thought, I think you are right. (For all practical purposes: yes, you'd need some slight horizontal component.) I suspect the person creating the problem didn't realize this. (I suspect this is not a textbook problem.)
 
Doc Al said:
On second thought, I think you are right. (For all practical purposes: yes, you'd need some slight horizontal component.) I suspect the person creating the problem didn't realize this. (I suspect this is not a textbook problem.)
It is a college assessed problem bit annoying really
 
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