Solving y=e^{t-t^2/2}: Luck or Methodology?

[Wxfsa]

I know y=e^{t-t^2/2} is a solution but how do I reach it? I tried substituting y=uv, making u' terms disappear then I noticed that the resulting u''=(__)u could be solved by a gaussian but this seems like luck to me

 

[AdityaDev]

Have you tried substituting y=e^kx?

 

[Wxfsa]

Have you tried substituting y=e^kx?

e^{kx} cannot be a solution but I decided to try e^{k(x)} which gave me a ricatti equation and after I substituted k=q\frac{p'}{p} I got the original equation

edit: this is the solution
c_1e^{\frac{-x^2}{4}+x}+c_2e^{\frac{-x^2}{4}+x} \int ^x e^{\frac{-s^2}{2}+2s}ds

 

[Mark44]

A little nitpicky, but y'' + ty' + ty is not an equation (differential or otherwise), so it doesn't make any sense to talk about a solution. Is the full equation y'' + ty' + ty = 0?

 

[Wxfsa]

A little nitpicky, but y'' + ty' + ty is not an equation (differential or otherwise), so it doesn't make any sense to talk about a solution. Is the full equation y'' + ty' + ty = 0?

yes

 

[Svein]

A little nitpicky, but y'' + ty' + ty is not an equation (differential or otherwise), so it doesn't make any sense to talk about a solution. Is the full equation y'' + ty' + ty = 0?

More nitpicking: Is y supposed to be a function of t or a function of x with t as a parameter?

 

[Wxfsa]

More nitpicking: Is y supposed to be a function of t or a function of x with t as a parameter?

you don't have to answer the question if you don't want to

 

[Wxfsa]

I actually solved this qustion after much work, however I do not like m solution. It would be great if someone could link me somewhere that derives error function laplace transforms

 

[Mark44]

More nitpicking: Is y supposed to be a function of t or a function of x with t as a parameter?

you don't have to answer the question if you don't want to

Of course that's true, but if you're asking for help with a problem, it's best to provide as much information about the problem as you can.