1. The problem statement, all variables and given/known data y = -2sin2(x+[pi/6])+1 for x [-pi, pi] 3. The attempt at a solution set y=0, 1/2 = sin2(x+[pi/6]) pi/6 = 2(x+[pi/6]), where pi/6 is the base angle Now because of the 2 infront of the (x+[pi/6]), I consider twice the domain, i.e. [-2pi, 2pi]. pi/6 is positive, and sin is positive in 1 & 2 quadrants. therefore, 2(x+[pi/6]) = pi/6, 5pi/6, -7pi/6, -11pi/6. divide by 2: (x+[pi/6]) = pi/12, 5pi/12, -7pi/12, -11pi/12. subtract [pi/6] from both sides: x = -pi/12, 3pi/12, -9pi/12, -13pi/12. This is my problem. Is -13pi/12 an issue since it is outside the original domain, or is it still ok since it is inside the modified domain [-2pi,pi]? the answer has x values of -pi/12, 3pi/12, -9pi/12, 11pi/12, so my only issue is the last value. What has gone wrong!?