Solving y + y = 2/sin(x) using Undetermined Coefficients

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Homework Help Overview

The problem involves solving the differential equation y" + y = 2/sin(x) using the method of undetermined coefficients. The original poster expresses uncertainty about how to apply this method and questions the existence of a particular integral for sin(x).

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of variation of parameters and the potential for rewriting sin(x) in exponential form. There are differing opinions on the existence of a particular integral for sin(x) and the implications of having it in the denominator.

Discussion Status

The discussion is ongoing with various perspectives being explored. Some participants suggest that a particular integral exists, while others emphasize the need for variation of parameters. There is no explicit consensus, but multiple interpretations are being considered.

Contextual Notes

Participants note the complexity introduced by the presence of sin(x) in the denominator and the implications for finding a particular solution. There is also mention of homework constraints regarding the methods that can be used.

cimmerian
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Homework Statement



y" + y = 2/sin(x)

solve for y

Homework Equations



I tried to use variation of parameters to solve this but I don't know how to check it.

The Attempt at a Solution



y = -2xcosx + (constant)cosx + 2ln(sin(x))sinx + (constant)sinx

How do I do this using Undetermined coefficients? I can't find a basis for the null space of 2/sinx
 
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I don't think there exists a PI for sin(x), you may need to use variation of parameters to solve the problem since you get two solutions for the homogene\eous equation.
 
Of course there is.

Anytime you see a sin or cos in differential equations theory you can rewrite it as an exponential. But for an actual particular solution, you can guess a linear combination of sin and cos.
 
cimmerian said:

The Attempt at a Solution



y = -2xcosx + (constant)cosx + 2ln(sin(x))sinx + (constant)sinx

This solution is correct,you can check it by differentiating it and subbing it back into the DE.

snipez90 said:
Of course there is.

Anytime you see a sin or cos in differential equations theory you can rewrite it as an exponential. But for an actual particular solution, you can guess a linear combination of sin and cos.

If the sin(x) is in the denominator and you write that in terms of eix and e-ix, you'd have those two on the denominator as well?
 
You said a particular integral for sin, and the use of / threw me off. But I agree for csc you would use variation of parameters or Green's functions.
 
thanks
 

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