What is the equation of a line with given intercepts?

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To find the equation of a line with a y-intercept of -2 and an x-intercept of -1, the coordinates (0, -2) and (-1, 0) are used. The slope (m) can be calculated as the change in y divided by the change in x between these two points. Using the formula y = mx + b, the slope is determined to be 2. Substituting the slope and the y-intercept into the equation yields y = 2x - 2. This provides the complete equation of the line based on the given intercepts.
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Homework Statement



write an equation of the line:

y intercept: negative 2
x intercept: negative 1

Homework Equations


y


The Attempt at a Solution



i know its y equals mx plus b

So b would equal negative two, but what about the y and the slope
 
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The x-intercept is the point where y = 0. In this case, that is at x = -1. If you plug that information into the general formula you will get an equation just for m.
 
The slope, m, is the change in y divided by the change in x between two points (rise over run). You have two points, so you can find the slope.
 
MoreZitiPlease said:
[y intercept: negative 2
x intercept: negative 1

i know its y equals mx plus b

Hi MoreZitiPlease! :smile:

If you're not sure, write out the known coordinates:

You know (0,-2) and (-1,0) are on the line.

So -2 = m.0 + b

0 = m.(-1) + b. :smile:
 
Standard Form equation for a line: Ax + By = C.

You already have two points and they are the axes intercepts.
A*0 + B*(-2) = C;
A*(-1) + B*0 = C,
But those might not help you since you get one equation with two unknowns.
YOUR INERCEPTS are (0, -2) and (-1, 0), so just resort to y=mx+b general form and find the slope using the known points. Since you already have the y intercept, you can now plug all information into the general form.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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