Some sort of transform to find the log of a series

AI Thread Summary
The discussion focuses on the challenge of calculating the incomplete gamma function for large arguments using a programming language with limited numerical precision. The user seeks a method to transform the sum of terms into a form that allows for logarithmic manipulation, as directly summing the logarithms does not yield the desired result. Suggestions include clarifying the programming constraints and considering the use of specialized arbitrary precision libraries. A reference to a FORTRAN implementation of the incomplete gamma function is provided as a potential resource. The importance of verifying the accuracy of the routine against established numerical libraries is also emphasized.
onanox
Messages
15
Reaction score
0
I am trying to write a computer program that involves finding 2 very large numbers (several thousand digits) and dividing them to get a reasonable sized number.
the first number is a value of the gamma function, which can be defined as a product and thus easy to reduce with logs (find the sum of the log of each term).

hoewever the second number is a value of the incomplete gamma function, which AKAIK can only be defined as a sum. clearly, if I just log each term and sum them, id get the log of the product and thus, no dice. However, if I could find some transform for each term, that when summed would equal the log of the total sum, my problems would be solved.

Has anyone heard of anything like this?
 
Mathematics news on Phys.org
the problem is that each term in the series is too large to compute with standard data types, and that thread defines a product based on a sum and thus will not work.
 
A time honored way of answering a internet post about "How do I do this..." is to reply "You don't want to do that...". It isn't necessarily relevant to your post, but it might be wise to explain exactly what you are trying to do - in case there is some special trick that applies to the situation but not in general or in case there is a way to avoid the problem altogether.

You should also clarify whether if you are determined not to use a specialized arbitrary precision numerical library like GNU Bignum in your program. Are you trying to get this to work in ordinary double precision floating point arithmetic?
 
good point, I guess I was a bit vague.
I am trying to calculate the incomplete-gamma function specifically for large arguments (around 50,000).
I am using as3 to program it, and there isn't any flexibility on the language.
 
onanox said:
I am trying to calculate the incomplete-gamma function specifically for large arguments (around 50,000).
I am using as3 to program it,

Well, at least the question isn't "How do I model nuclear reactions using my Excel spreadsheet?".

I did a Google search on the words: large values incomplete gamma function
I found this PDF which reports how it was coded in FORTRAN:

http://www.google.com/url?sa=t&sour...p_msDQ&usg=AFQjCNGNyI6Ky4KtzwHvc-IgHDANnCXPmA

(See section D.)

One problem you are going to have is checking your routine. There is always the possibiity of typos in you coding or even in the printed matter you based the code upon.
It's handy to be able to compare your answers to output from a standard numerical library.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top