- #1
Jacob87411
- 171
- 1
A single conservative force acts on a 5.00 kg particle. The equation Fx = (2x + 4) N describes this force, where x is in meters. As the particle moves along the x-axis from x = 2.60 m to x = 6.20 m, calculate the following.
(a) the work done by this force
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Alright this seems pretty straight forward...W=FD, distance equals the change in X which is (6.2-2.6) which equals 3.6...The force acting on the particle is where I get a bit confused. F=2x+4...do you do it with x=6.2 or 2.6? Or do you find the value of 6.2 and subtract is from 2.6? Thanks for any help
(a) the work done by this force
-----------------
Alright this seems pretty straight forward...W=FD, distance equals the change in X which is (6.2-2.6) which equals 3.6...The force acting on the particle is where I get a bit confused. F=2x+4...do you do it with x=6.2 or 2.6? Or do you find the value of 6.2 and subtract is from 2.6? Thanks for any help