Sound energy passing through a hole

AI Thread Summary
To solve the problem of calculating the energy passing through a hole from a sound wave with an intensity level of 80 dB, first convert the decibel level to intensity using the formula dB = 10log10(I/I0), where I0 is the reference intensity (1 x 10^-12 W/m²). This results in an intensity of approximately 0.01 W/m². Multiply this intensity by the cross-sectional area of the hole (3 m²) to find the total power in watts, which is 0.03 W. Over a duration of 10 minutes, convert the time to seconds and multiply by the power to find the total energy in joules, resulting in 18 J. The solution demonstrates the relationship between sound intensity, area, and energy over time.
ashi611
Messages
1
Reaction score
0

Homework Statement


"A continuous sound wave with a sound intensity level of 80dB passes through a hole in a wall which has a cross-sectional area of 3m^2. How much energy passes through this hole in 10 minutes, in joules?"

If anyone can show me how this problem is solved it's be much appreciated. Thanks



Homework Equations



dB = 10log10 (I/Io)

The Attempt at a Solution

 
Physics news on Phys.org
Suppose instead of units of dB you had Joules per square meter per second (a.k.a. Watts per square meter a.k.a. Intensity)

Then how would you solve the problem?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top