Space traveler and time dilation

chenying
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Homework Statement



A space traveler takes off from Earth and moves at speed 0.81c toward the star Vega, which is 26 ly distant.

How much older will Earth observers calculate the traveler to be (according to her) when she reaches Vega than she was when she started the trip?

Homework Equations



t = t prime / sqr. root of (1 - v^{}2/c^{}2)

the v and the c are supposed to be squared.

The Attempt at a Solution



I used the above equation to first find the time that has elapsed in earth, which came out to be 32.0988 years.

Then i used that same number and set it as my t so i can find the amount of time again, since they asked for the age the Earth observers will see the traveler based on her age
 
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chenying said:

Homework Statement



A space traveler takes off from Earth and moves at speed 0.81c toward the star Vega, which is 26 ly distant.

How much older will Earth observers calculate the traveler to be (according to her) when she reaches Vega than she was when she started the trip?

Homework Equations



t = t prime / sqr. root of (1 - v^{}2/c^{}2)

the v and the c are supposed to be squared.

The Attempt at a Solution



I used the above equation to first find the time that has elapsed in earth, which came out to be 32.0988 years.

Then i used that same number and set it as my t so i can find the amount of time again, since they asked for the age the Earth observers will see the traveler based on her age

When you use tex tags, put the whole equation inside the tags... like this. Click on the formula to see how it was typeset.
t = \frac{t'}{\sqrt{1 - v^2/c^2}}

What you've done sounds good. What did you get?
 
I got 54.7359 years, which was wrong. The wording of the question is really confusing and I do not know how to go about it.
 
chenying said:
I got 54.7359 years, which was wrong. The wording of the question is really confusing and I do not know how to go about it.

I think you have mixed up your t and t'. In the equation, t is elapsed time as measured by someone on Earth. t' is the elapsed time in the frame of the traveler
 
ok I understand that, but the wording of the question really confuses me. They want the how much older the woman is (based on her frame) but from their frame??
 
chenying said:
ok I understand that, but the wording of the question really confuses me. They want the how much older the woman is (based on her frame) but from their frame??

Not so much "based on her frame", but rather how much she herself has aged. You can calculate how much older she is in her own experience (that is, "according to her") in any frame you like. They all give the same answer for how much she herself has aged.

Cheers -- sylas
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?

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