Spatially Homogeneous Scalar Field on Spacetime: Showing $\nabla^2 f$

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If ##f## is a "spatially homogeneous" scalar field on spacetime ##ds^2 = dt^2 - a^2(t) \delta_{ij} dx^i dx^j## then show that ##\nabla^2 f = \ddot{f} + 3H \dot{f}##. Should be easy if I knew what the condition on ##f## is, i.e. ##\nabla^2 f = \partial_{\mu} \partial^{\mu} f = \ddot{f}- a^{-2}(t) \delta^{ij} \partial_i \partial_j f = \dots##?
 
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Spatially homogeneous = does not depend on spatial position. In other words, ##f## is a function of ##t## only.
 
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I messed up the double covariant, should be:\begin{align*}
\nabla^2 f &= \nabla_{\mu}(\partial^{\mu} f) \\
&= \partial_{\mu} \partial^{\mu} f + g^{\nu \rho} \Gamma_{\mu \nu}^{\mu} \partial_{\rho} f \\
&= \partial_t^2 f + 3H \partial_t f
\end{align*}(##\Gamma_{0i}^{j} = H\delta^{j}_{i}##)
 
Indeed. Only the time derivatives survive since the field only depends on t. Then it is just a matter of finding the appropriate trace of Christoffel symbols.