Special relativity: 2d metric components

AI Thread Summary
The discussion revolves around a 2D metric defined as ds² = x²dx² + 2dxdy - dy², where the user is tasked with finding the contravariant and covariant components of the metric tensor, g_{ab} and g^{ab}. Initially, the user assumes a Euclidean metric, leading to the conclusion that off-diagonal components are zero, which is incorrect for this metric. The lecturer clarifies that the metric is non-diagonal, with g_{xx} = x², g_{yy} = -1, and g_{xy} = g_{yx} = 1, indicating the need to consider these non-zero off-diagonal elements. The user also questions the assumption of symmetry in tensors and the implications of mixed components in summation, highlighting the complexities of understanding metric tensors in special relativity.
Uku
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An SR question again, exam on monday.

Homework Statement


I'm given a 2D metric as:

ds^{2}=x^{2}dx^{2}+2dxdy-dy^{2}

I have to first find the contravariant and covariant components of the metric, or g_{ab} and g^{ab}

Homework Equations


General expression of a metric tensor

ds^{2}=g_{\mu\nu}dx^{\nu}dx^{\mu}

The Attempt at a Solution


Since the metric is 2D, I can write the above as (with significance to me)

ds^{2}=g_{00}dx^{0}dx^{0}+g_{11}dx^{1}dx^{1} 1)

Now this is assuming that the metric is Euclidean, with the components not on the main diagonal being zero.

Now using "common sense" I know that in Euclidean space ds^{2}=dx^{2}+dy^{2}
Comparing the two I can assume that g_{00}=1 and g_{11}=1, which seems to make sense, because then the Phythagoras theroem emerges from 1)

But! The lecturer has written down the metric formally as:

g_{ab}=\left[ \begin{array}{cc} g_{xx} & g_{xy} \\ g_{yx} & g_{yy} \end{array} \right]

And now, out of the blue for me, he has written g_{xx}=x^{2} and g_{yy}=-1 Why so?

Further, he has written that the metric is non-diagonal, meaning that

\left[ \begin{array}{cc} g_{xx} & g_{xy} \\ g_{yx} & g_{yy} \end{array} \right]=\left[ \begin{array}{cc} x^{2} & 1 \\ 1 & -1 \end{array} \right]

the elements aside the main diagonal are not zero. I'm puzzled at this point. The non-diagonal metric means that the summation 1) is a false assumption by me, because the components are not zero. How do I approach this 2D metric to find the g_{ab} and g^{ab}?
 
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Uku said:
An SR question again, exam on monday.

Homework Statement


I'm given a 2D metric as:

ds^{2}=x^{2}dx^{2}+2dxdy-dy^{2}

I have to first find the contravariant and covariant components of the metric, or g_{ab} and g^{ab}

Homework Equations


General expression of a metric tensor

ds^{2}=g_{\mu\nu}dx^{\nu}dx^{\mu}

The Attempt at a Solution


Since the metric is 2D, I can write the above as (with significance to me)

ds^{2}=g_{00}dx^{0}dx^{0}+g_{11}dx^{1}dx^{1} 1)

Why no g_{01} and g_{10} terms?
 
Because I assumed the metric to be Euclidean, where the components not on the main diagonal are zero, meaning that the g_{01} and g_{10} are zero, meaning I do not have to consider them in the summation. But now that you put my attention to it, ill look into it.

EDIT: I see some light!
 
Why assume the metric is Euclidean (although you should assume it is symmetric)? The metric is defined by the equation ds^{2}=x^{2}dx^{2}+2dxdy-dy^{2}.
 
Solved it! I assumed because I wanted to start solving the assignment from somewhere.

Why should I assume symmetry? Because I can't prefer any direction over others?
 
I have a second question about symmetry. My my course material, I have a following statement about symmetric tensors:

S^{\mu}_{\;\nu}=S^{\;\mu}_{\nu}\equiv S^{\mu}_{\nu}

What does the spacing in the indexes mean?

EDIT: I see it means that the tensor has mixed components, but what does that mean when I start the summation? I'm seeing that I can't sum, because the indexes are both cotravariant or covariant.
 
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