Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Special Relativity Spacetime Intervals

  1. Jan 25, 2012 #1
    Just a quick question on spacetime intervals in spacetime. Why is the spacetime interval between two events given by Δs^2 = -c^2(Δt^2) + Δx^2 + Δy^2 + Δz^2, rather than c^2(Δt^2) + Δx^2 + Δy^2 + Δz^2 (as if it were the distance between two points in four spatial dimensions)? Or more succinctly, why is the time component of the spacetime interval negative?
     
  2. jcsd
  3. Jan 25, 2012 #2
    Because the first one is frame invariant (it takes the same value in every frame), whereas the second one is not.

    Take the Lorentz Transformation:

    [itex]\Delta x'=\gamma (\Delta x-v\Delta t)[/itex]
    [itex]\Delta t'=\gamma (\Delta t-v\Delta x/c^2)[/itex]

    Now try calculating [itex](\Delta x')^2-(c\Delta t')^2[/itex]. You'll find that [itex](\Delta x')^2-(c\Delta t')^2=(\Delta x)^2-(c\Delta t)^2[/itex].

    If you try doing the same thing with [itex](\Delta x')^2+(c\Delta t')^2[/itex] you'll see that [itex](\Delta x')^2+(c\Delta t')^2 \neq (\Delta x)^2+(c\Delta t)^2[/itex]
     
  4. Jan 25, 2012 #3

    ghwellsjr

    User Avatar
    Science Advisor
    Gold Member

    The whole point of the spacetime interval is to arrive at something analogous to a distance in space and/or a period of time that comes out the same no matter what frame you do the calculation in. If you use the second formula, it doesn't come out the same in all frames whereas the first one does.
     
  5. Jan 25, 2012 #4
    elfmotat and ghwellsjr summed it up pretty well. Here's basically the same point they've made using some graphics.
    4_D_Metric_SpaceE.jpg
    From this point of view you can see why the Pythagorean theorem doesn't work for the blue guy when he tries to compute an invariant value for a red interval.

    In a way, the root cause of this situation (from the standpoint of the space-time diagram) has to do with the unique orientation of the blue and red X1 and X4 coordinates. For example, the direction the blue guy moves in the 4-dimensional universe determines the slope of his world line (his X4 coordinate slope with respect to the black rest system).

    Now, the mysterious aspect of special relativity is that blue's X1 coordinate (his 3-D cross-section view of the 4-D universe) rotates such that the 45-degree photon world line always bisects the angle between X4 and X1. This is a perfectly general phenomenon, regardless of the observer's speed, holding for any observer moving relative to the black rest system. Accordingly, this explains why the speed of light is always c, for any frame of reference.

    So, in a way, you could ask of nature: Why is it that the observer's X1 axis always rotates in that special manner when the X4 rotates? One possible answer that has been suggested is that consciousness can only pick out a cross-section view of the 4-D universe that is intelligible. And The 4-dimensional objects are arranged geometrically so as to present symmetric relationships among objects that are consistent with the laws of physics. Some would argue that this underlies the discovery of laws of physics. And this is consistent with the fact that the laws of physics are the same in all Lorentz frames.
     
    Last edited: Jan 25, 2012
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Special Relativity Spacetime Intervals
  1. Spacetime interval (Replies: 36)

  2. Spacetime Interval (Replies: 13)

Loading...