Special Relativity: Time dilation

AI Thread Summary
The discussion centers on the conceptual understanding of time dilation in special relativity as experienced by observers on a spaceship and on Earth. The Earth observer calculates the travel time for the spaceship as T1 = L/v, noting that the spaceship's clock runs slower, advancing by T0 = T1/ɣ. Conversely, the spaceship observer perceives the Earth observer's clock as ticking slower, yet concludes that the total travel time in their frame is less than that measured by the Earth observer. The conversation highlights the importance of the "relativity of simultaneity" and suggests using three clocks to analyze the situation accurately. Proper time is defined as the time measured by a single clock in a single location, emphasizing the need for clarity in comparing different frames of reference.
ntknow
Messages
3
Reaction score
0
Hello. This is not a concrete problem, rather conceptual question.

Homework Statement


2. Homework Equations
3. The Attempt at a Solution [/B]
Spaceship with speed v with respect to the Earth is traveling from the Earth to say some distant star, which is distant L apart from the Earth looking by observer who is in the Earth frame. Analysis from both observers point of view:
Earth observer:
observes that spaceship travels the distance in time T1 = L/v. In addition to that, he observes that clock in the spaceship during the travel advances by T0=T1/ ɣ, i.e. less than his clock.

Spaceship observer:
by relativity he sees that the Earth observer's clock is ticking slower than his clock, however, by above argument total travel time in his frame is smaller than in the Earth frame. Additional facts are that he observes length, L, contracted and time reading difference between clock in the Earth and clock, for example, in the star.

Problem for me:
Could someone summarise / make me clear / point out flaws in the reasoning why total travel time is still smaller as observed by spaceship observer than by the Earth observer if spaceship observer during all the time then Earth gets farther from him sees the Earth observer's clock running slower?
 
Last edited:
Physics news on Phys.org
ntknow said:
Hello. This is not a concrete problem, rather conceptual question.

Homework Statement


2. Homework Equations
3. The Attempt at a Solution [/B]
Spaceship with speed v with respect to the Earth is traveling from the Earth to say some distant star, which is distant L apart from the Earth looking by observer who is in the Earth frame. Analysis from both observers point of view:
Earth observer:
observes that spaceship travels the distance in time T1 = L/v. In addition to that, he observes that clock in the spaceship during the travel advances by T0=T1/ ɣ, i.e. less than his clock.

Spaceship observer:
by relativity he sees that the Earth observer's clock is ticking slower than his clock, however, by above argument total travel time in his frame is smaller than in the Earth frame. Additional facts are that he observes length, L, contracted and time reading difference between clock in the Earth and clock, for example, in the star.

Problem for me:
Could someone summarise / make me clear / point out flaws in the reasoning why total travel time is still smaller as observed by spaceship observer than by the Earth observer if spaceship observer during all the time then Earth gets farther from him sees the Earth observer's clock running slower?

Have you covered the "relativity of simultaneity" or the "leading clocks lag" concept yet?
 
PeroK said:
Have you covered the "relativity of simultaneity" or the "leading clocks lag" concept yet?

Yes, I am familiar with these concepts.
 
ntknow said:
Yes, I am familiar with these concepts.

Can you analyse the journey from the ship's RF? Hint: you need three clocks. Two "rest" clocks: one on Earth and one at the distant star. And one clock moving with the ship.
 
.
 
Last edited:
Restating PeroK's comment: Proper time is measured by a single clock in a single place.
Only the clock on the spaceship (in the frame of) meets this requirement.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top