Specific heat in izobaric process

Click For Summary

Homework Help Overview

The discussion revolves around calculating specific heat at constant pressure (Cp) from mass specific heat and molar mass, particularly in the context of gases and water. Participants are exploring the relationships between specific heats and the implications of different conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand how to derive Cp from mass specific heat and molar mass, with some questioning the assumptions about the state of the substance (gas vs. water). There is also a focus on the relationship between Cp and Cv, particularly the equation Cp - Cv.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the specific heat values for different substances. Some guidance has been offered regarding the calculations, but multiple interpretations and assumptions are still being explored.

Contextual Notes

There is a mention of specific heat values for water and the assumption that the specific heat discussed is at constant volume for gases. The context of perfect gases is also noted, which may influence the calculations and relationships being discussed.

player1_1_1
Messages
112
Reaction score
0

Homework Statement


how can I calculate specific heat at constant pressure from mass specific heat and mole mass?
 
Physics news on Phys.org
player1_1_1 said:

Homework Statement


how can I calculate specific heat at constant pressure from mass specific heat and mole mass?
I assume that this is a gas and the mass specific heat is at constant volume.

If so, use mass specific heat (heat energy/unit mass) and mass/mole to determine mole specific heat at constant volume (Joules /(mol. K)).

What is the relationship between Cp and Cv for a gas? (Hint: what is Cp-Cv?)

AM
 
thanks for answer:) this is perfect gas and the specific heat is not volume, but this which is ptex]4200\frac{J}{kg\cdotK}[/tex] for water - how can I calculate this from this?
 
thanks for answer:) this is perfect gas and the specific heat is not volume, but this which is [tex]4200\frac{J}{kg\cdot K}[/tex] for water - how can I calculate this from this?
 
Last edited:

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
54
Views
10K
  • · Replies 1 ·
Replies
1
Views
1K