Speed of orbiting planet given eccentricity of orbit

AI Thread Summary
The discussion focuses on calculating the ratio of the lengths of the major to minor axes of a planet's orbit with an eccentricity of 0.4 and the ratio of its speeds at the ends of the major axis. The ratio of the axes is determined to be approximately 1.0911. For the speed ratio, the user initially struggles with a messy expression using kinetic energy but later finds success using conservation of angular momentum. The approach simplifies the problem significantly, leading to the correct answer. Overall, the conversation highlights the importance of different methods in solving orbital mechanics problems.
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Homework Statement


If the eccentricity of a planet's orbit about the sun is 0.4, find (a) the ratio of the lengths of the major to minor axes of the planet's orbit, and (b) the ratio of the speeds of the planet when it is at the ends of the major axis of its elliptical orbit.


Homework Equations



E=\dfrac{1}{2} mv^2 + \dfrac{-GMm}{r} + \dfrac{L^2}{2mr^2}

The Attempt at a Solution



The first part is rather short and sweet:

\dfrac{a}{b}=\dfrac{1}{\sqrt{1-\epsilon^{2}}}=\dfrac{1}{\sqrt{1-0.4^{2}}}\approx1.0911

But I have no idea how to proceed on the second part. If I take the ratio of the kinetic energies I get a very messy expression and have problem eliminating the total energy E. Is there a more elegant way to do this?
 
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hi

orbital speed is given by

v=\sqrt{\mu\left(\frac{2}{r}-\frac{1}{a}\right)}

where \inline{\mu =G(M+m)} is the standard gravitational parameter. and r is the distance from the sun(focus). at the farthest point in the orbit from the sun
\inline{r=(1+e)a} and the closest point we have \inline{r=(1-e)a}
where a is semi major axis length. use this info

Newton
 
Last edited:
Hey thanks for your help. I tried using your approach but I couldn't simplify it so I tried using conservation of angular momentum and got the correct answer. Simpler than I expected.
 
well algebra is pretty straight forward I guess.
 
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