Speed of Waves traveling on a taut string

AI Thread Summary
To determine the time it takes for a wave to travel along a taut string, the relevant equations are v=√(T/M) and M=mass/length. The string has a length of 9.5 m, a mass of 55 g, and is under a tension of 6 N. After converting the mass to kilograms and the length to meters, the velocity of the wave is calculated. However, the final answer should focus on finding the time, not just the velocity, which is a common mistake in solving the problem. The correct approach involves calculating the wave speed first and then using it to find the time taken for the wave to travel the length of the string.
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Homework Statement



If the string is mass 9.5 m long, has a mass of 55g and is pulled taut with a tension of 6N, how much time does it take for a wave to travel from one end of the string to the other?

Homework Equations



v=√(T/M)
M=mass/length

The Attempt at a Solution



First I converted 9.5m to 950cm and 55g to .055kg
then i divided .055/950 and divided 6 by the answer I got for that, and then took the square root. I got 320 as my answer (in 2 sigfigs) but it is saying that is incorrect.
 
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eagles12 said:

Homework Statement



If the string is mass 9.5 m long, has a mass of 55g and is pulled taut with a tension of 6N, how much time does it take for a wave to travel from one end of the string to the other?

Homework Equations



v=√(T/M)
M=mass/length

The Attempt at a Solution



First I converted 9.5m to 950cm
Why would you convert to cm units?

In the SI system of units, the standard units are meters, kilograms, seconds.

There's nothing wrong with moving to a different system, as long as you are consistent. If you convert length from meters to centimeters, you should also convert Newtons to some other units. Newtons have units of kg m/sec2. So you'd have to convert that to kg cm/sec2.

But why bother? It's easier to just stick with SI units.
and 55g to .055kg
Now that conversion I can understand. :approve:
then i divided .055/950 and divided 6 by the answer I got for that, and then took the square root. I got 320 as my answer (in 2 sigfigs) but it is saying that is incorrect.
'Sounds like you're trying to calculate the velocity. That's fine: it's an intermediate step. But don't consider it your final answer. The problem statement is asking you for time, not velocity.
 
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