Speed, Velocity, Acceleration, etc. at t=0

AI Thread Summary
Speed, velocity, and acceleration are undefined at Δt=0 when using average formulas, as they involve division by zero. Instead, these quantities are defined through derivatives, which utilize limits to provide instantaneous values. At t=0, average velocity and acceleration cannot be calculated without a finite time interval. The discussion emphasizes that derivatives and limits are fundamentally linked, with derivatives being defined as limits. Therefore, understanding these concepts requires recognizing the transition from average to instantaneous measurements.
logan3
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I was wondering how speed, velocity, acceleration and anything with a \Delta t in the denominator are defined at \Delta t=0? Other than approximating with limits, aren't they undefined?

Ex: {\vec{v_{avg}} = \frac{\vec{s}}{\Delta t}}, at t = 0 \Rightarrow {\vec{v_{avg}} = \frac{\vec{s}}{0}} \Rightarrow {\vec{v_{avg}}} = und.

{\vec{a}} = \frac{\vec{v_{f}}-\vec{v_{i}}}{\Delta t}, at t = 0 \Rightarrow {\vec{a}} = \frac{\vec{v_{f}}-\vec{v_{i}}}{0} \Rightarrow {\vec{a}} = und.

Thank-you
 
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Well as mfb pointed out, they are defined by derivatives, and thus they are instantaneous and not average.
There is no average velocity/acceleration defined at a given time t=0, but in some interval Δt. So your formulas are wrong...

For \Delta t \rightarrow 0 you have:

a(t_0)= lim_{\Delta t \rightarrow 0} \frac{ u(t_{0}+ \Delta t) - u(t_{0})}{\Delta t}
You can expand the u(t_{0}+ \Delta t) around t0:
u(t_{0}+ \Delta t) \approx u(t_{0})+ \Delta t \frac{du(t)}{dt}|_{t=t_{0}}
(you could try to write more terms in the series so avoid the approximation symbol, but later on you are going to take the limit of \Delta t \rightarrow 0 and so you see only the first power would survive-the rest would have \frac{(\Delta t)^{2}}{\Delta t} \rightarrow 0 in that limit).

thus:

a(t_0)= lim_{\Delta t \rightarrow 0} \frac{ u(t_{0})+ \Delta t \frac{du(t)}{dt}|_{t=t_{0}} - u(t_{0})}{\Delta t}=\frac{du(t)}{dt}|_{t=t_{0}}

As for a the acceleration (rate of change of velocity), a similar way is used for u, but with x instead of u (since it's the rate of change of position)

But there is no distinction between derivatives and limits... derivatives are mathematically defined by the first limit I wrote...now if you prefer listening to the name "derivative" instead of "limit" it's up to you. But all derivative properties are proved by their definition as limits.
 
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