Using a Newton equation for position and substituting (v-v0)/a for t you can get the following formula:(adsbygoogle = window.adsbygoogle || []).push({});

v^2= v0^2+2a(x-x0) where v^2 is supposedly speed. I understood speed to be tha magnitude of velocity which is the sqrt of the sum of the squares of the components (i.e. sqrt(vx^2+vy^2+vz^2)). I seem to be missing something.... how is speed then v^2? I am sure it is right in front of my face but I am just not seeing it.

TIA

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# Speed with constant acceleration

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