atomicpedals
- 202
- 7
Homework Statement
Given that Lz(x+iy)m=m\hbar(x+iy)m. Show that L+=(x+iy)m.
2. The attempt at a solution
I'm probably grasping at straws here, but when I see the expression for Lz I instantly go to Lz|lm>=m\hbar|lm>. This then leads me to suspect that |lm>=(x+iy)m. Is this correct, and how on Earth does it get me any closer to what I want to show for the raising operator?