Spin 1/2 in B-field polarization direction?

valtorEN
Messages
36
Reaction score
0
spin 1/2 in B-field polarization direction??

Homework Statement



A spin 1/2 particle with magnetic momnet mu=mnot*sigma is placed in

uniform B-field, where the magnetic field is pointing in (theta,phi) direction

in spherical coordinates

At t=0, the particle is in the (1 0) state, i.e. sigma(z)=1 and the polarization

direction is =e3 (z hat direction).

Find out the polarization direction of the particle at t>0.



Homework Equations



the theory of spin is like angular momentum

magnetic moment mu=-gamma*S

S=spin matrix

S^2|sm>=hbar^2s(s+1)|sm>

and Sz|sm>=hbar*m|sm>


The Attempt at a Solution



Not sure how to approach this one, i assume that the particle is at rest in the B-field

the Hamiltonian for a spinning charged particle in B-field is H=-gamma*(B dot S)

this is a time-DEPENDENT perturbation

how can i realte what is given to the polarization direction?

cheers
nate:biggrin:
 
Physics news on Phys.org
ok, let me try this again

H=-mu*B (this is the interaction energy between spin and B-field)

for a particle of spin 1/2, with magnetic moment mu=mu(s)*S

the Hamiltonian is h=1/2*m(p-q/c*A)^2-mu*B

B=BX+BY+BZ (where i need to put B into spherical coordinates)

so if i have the B-field in the z-direction, A=(-By,0,0)

so...

H=1/2*m[(px^2+py^2+pz^2)+(2*q*B*px/c)*y+(qB/c)^2*y^2]-(mu*B/S)Sz

is this correct? i have a Hamilton with Sz in it which is given as sigma(z)=1 (pauli spin matrix)
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top