What is the Energy Transfer in a Spring and Oscillation Collision?

AI Thread Summary
The discussion centers on a physics problem involving a bullet colliding with a block connected to a spring. Participants suggest using conservation of energy and momentum to solve for the bullet's emerging speed and the mechanical energy lost during the collision. The equation .5kx^2 = .5mv^2 is proposed to relate the spring's potential energy to the kinetic energy of the bullet and block system. There is some frustration expressed about finding relevant resources or previous discussions on the topic. The conversation highlights the importance of correctly applying physical principles to analyze energy transfer in collisions.
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A 5.00 g bullet moving with an initial speed of v0 = 405 m/s is fired into and passes through a 1.00 kg block, as in Figure P13.58. The block, initially at rest on a frictionless horizontal surface, is connected to a spring with a spring constant of 950 N/m.


Figure P13.58
(a) If the block moves 5.00 cm to the right after impact, find the speed at which the bullet emerges from the block.
m/s
(b) If the block moves 5.00 cm to the right after impact, find the mechanical energy lost in the collision. J


I don't know where to begin, its so frustrating
 
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Not that I wouldn't like to help you, but I'm almost 100% positive I've seen this exact picture in the last 2 or 3 weeks. I suggest you do some searching first. :wink:
 
I checked the thread and it wasnt much of a help

I tried to use conservation of momentum for this but it doesn't work
 
Try conservation of energy.
 
how do I set it up though

.5kx^2= .5mv^2?
 
The original kinetic energy will be the sum of the spring energy and the bullets remaining kinetic energy after impact.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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