Spring system inside an accelerating box

AI Thread Summary
The discussion revolves around a physics problem involving a mass suspended from a spring inside an accelerating box. The initial attempt to solve the problem incorrectly included the gravitational force and acceleration in the spring's force equation. The correct approach focuses on the change in the mass's position due to the box's upward acceleration, leading to the conclusion that the new equilibrium position can be calculated as ma/k. Participants clarify that the initial position can be assumed as zero, emphasizing the distinction between the spring's natural length and its loaded state. The conversation highlights the importance of understanding the mechanics of equilibrium in an accelerating frame.
physics517
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Homework Statement



A mass m is resting at equilibrium suspended from a vertical spring of natural length L and spring constant K inside a box.

The box begins accelerating upward with acceleration a. How much closer does the equilibrium position of the mass move to the bottom of the box?

Homework Equations



f=kx
f=ma

The Attempt at a Solution



so this is my f=ma statement

kx-mg=ma

then i solved for x to get x= m(a+g) / k

but this answer is wrong and the correct answer is

ma / k
 
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You are looking for the change in the mass' position from the initial equilibrium position, after the box has begun accelerating. What was its initial position?
 
gneill said:
You are looking for the change in the mass' position from the initial equilibrium position, after the box has begun accelerating. What was its initial position?

In other words, what was the equilibrium position of the mass before the box was accelerated?

 
hmm the problem doesn't specify that location.

Cant we just assume it to be at location 0
 
physics517 said:
hmm the problem doesn't specify that location.

Cant we just assume it to be at location 0

Sure. You can assign your zero position to that location. Just keep in mind that it isn't the same location as the end of the relaxed, unloaded spring.

Recapping what's happening:

1. Box at rest. Spring unloaded, natural length L.
2. Box at rest. Spring loaded with mass M, settles at equilibrium.
3. Box accelerating. Spring stretches more, assumes new equilibrium.

The question is (essentially) asking for the amount of stretching that takes place between items 2 and 3.
 
gneill said:
Sure. You can assign your zero position to that location. Just keep in mind that it isn't the same location as the end of the relaxed, unloaded spring.

Recapping what's happening:

1. Box at rest. Spring unloaded, natural length L.
2. Box at rest. Spring loaded with mass M, settles at equilibrium.
3. Box accelerating. Spring stretches more, assumes new equilibrium.

The question is (essentially) asking for the amount of stretching that takes place between items 2 and 3.


I think my problem was that i assumed L to be the spring's length when it was loaded. But what you stated makes sense now and it leads to the right answer.

excellent help. you gave me info but just enough to make me think and understand it

thank you
 
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