LAHLH
- 405
- 2
Does anyone know exactly how Srednicki identitifies the electromagnetic gauge field with his l,r,b fields. I know he is trying to match covariant derivatives, i.e.
D_{\mu} p=(\partial_{\mu}-il_{\mu})p with D_{\mu} p=(\partial_{\mu}-ieA_{\mu})p
and that he has set l_{\mu}=l_{\mu}^a T^a+b_{\mu}
and also match D_{\mu} n=(\partial_{\mu}-ir_{\mu})n with D_{\mu} n=(\partial_{\mu})n
and that he has set r_{\mu}=r_{\mu}^a T^a+b_{\mu}
But I don't seem to be able to work out the fine print of arriving at (90.20):
eA_{\mu}=l^3_{\mu}+r_{\mu}^3+1/2b_{\mu}
from these.
I guess it must be quite simple, and I thought maybe I should just expand the T^{a} gens in terms of Pauli then solve simultaneously, but this didn't quite seem to work out..
D_{\mu} p=(\partial_{\mu}-il_{\mu})p with D_{\mu} p=(\partial_{\mu}-ieA_{\mu})p
and that he has set l_{\mu}=l_{\mu}^a T^a+b_{\mu}
and also match D_{\mu} n=(\partial_{\mu}-ir_{\mu})n with D_{\mu} n=(\partial_{\mu})n
and that he has set r_{\mu}=r_{\mu}^a T^a+b_{\mu}
But I don't seem to be able to work out the fine print of arriving at (90.20):
eA_{\mu}=l^3_{\mu}+r_{\mu}^3+1/2b_{\mu}
from these.
I guess it must be quite simple, and I thought maybe I should just expand the T^{a} gens in terms of Pauli then solve simultaneously, but this didn't quite seem to work out..