Stable equilibium of a potential

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The discussion centers on a particle's motion in a potential defined by U(x)=U_0[2(x/a)^2-(x/a)^4]. Participants address three main questions: the angular frequency of oscillations around the stable equilibrium at x=0, the minimum speed required for the particle to escape to infinity, and the particle's position over time when starting from the origin with escape speed. The stable equilibrium point is confirmed to be at x=0, and the potential function's graph is suggested to aid in visualizing the energy needed for escape. Clarifications are requested regarding the expression for minimum speed and the interpretation of the third question about position versus velocity.
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Homework Statement


A particle of mass moving in one dimension has potential energy ##U(x)=U_0[2(x/a)^2-(x/a)^4]##, where #U_0# and ##a## are positive constants.
(i)What is the angular frequency ##w## of oscillations about the point of stable equilibrium?
(ii)What is the minimum speed the particle must have at the origin to escape to infinity?
(iii)At ##t=0## the particle is at the origin and its velocity is positive and equal in magnitude to the escape speed of part (d). Find ##x(t)##

The Attempt at a Solution


I have no idea about (i), though I know the stable equilibrium point is x=0.
My result of (ii) is ##\sqrt{\frac{-2U_0}{m}[2(x/a)^2-(x/a)^4]}##
But, here comes the problem. The speed at x=0 is 0, so it must stay at the origin forever.
I might get something wrong in obtaining the expression of (ii).
Any help would be appreciated.
 
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Plot the potential function. From that, you can understand what energy the particle needs to escape from the potential well.
As for (i) you need to find the angular frequency of small oscillations around x/a=0. If it is small, the fourth power can be ignored with respect to (x/a)^2 and the potential energy function approximates that of a spring.
I do not understand qestion (iii) What is x(x)? was not that v(x) instead?

ehild
 
The graph would be something like this ,
the potential at maxima (x=+-a) needs to be equated to KE
you will get velocity (min)
 

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