Standard Deviation of basketball player height

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SUMMARY

The discussion focuses on calculating the percentage of basketball players exceeding certain heights based on a normal distribution model. Given a mean height of 184 cm and a standard deviation of 5 cm, the participants utilize the empirical rule, stating that approximately 68% of data falls within one standard deviation, 95% within two, and 99.7% within three. Specific calculations for heights of 189 cm, 179 cm, between 174 cm and 199 cm, and over 199 cm are discussed, emphasizing the application of normal distribution principles.

PREREQUISITES
  • Understanding of normal distribution and its properties
  • Familiarity with standard deviation and mean calculations
  • Basic knowledge of statistical concepts such as percentiles
  • Ability to use statistical tools or calculators for probability calculations
NEXT STEPS
  • Learn how to calculate probabilities using the Z-score formula
  • Explore the use of statistical software like R or Python for normal distribution analysis
  • Study the empirical rule and its applications in real-world scenarios
  • Investigate the concept of confidence intervals in statistics
USEFUL FOR

Students studying statistics, data analysts, and sports statisticians interested in understanding player height distributions and their implications in basketball performance analysis.

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Homework Statement


The mean height of players in a basketball competition is 184 cm. If the standard deviation is 5 cm, what percentage of them are likely to be:
a) taller than 189 cm
b) taller than 179 cm
c) between 174 cm and 199 cm
d) over 199 cm cm tall?


Homework Equations


The textbook reads that often approximately 68 percent of the population will have a measure that fall sbetween 1 standard deviation either side of the mean, 95 percent 2 standard deviations either side of the mean, and 99.7 percent of the population 3 standard deviations either side of the mean.

The Attempt at a Solution


For the question above, how do I find the percentage? Using the information above, can I conclude that the percentile difference between s+1 and s-1 is 68 percent (where s= standard deviation, sorry I don't have the math application required by the website). Thank you.
 
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I think you could model the given information to a normal distribution i.e. X~N(184,25) and then use some method (calculator, tables etc.) to calculate the probability of a certain height range occurring.
 

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