How Does Changing Tension Affect Standing Wave Patterns and Antinode Formation?

AI Thread Summary
Changing the tension in a string affects the speed of wave propagation and the formation of standing waves. When tension is increased, the speed of the wave increases, leading to fewer nodes and antinodes for a constant frequency. A standing wave will form if the wavelength fits within the length of the string, which is determined by the relationship between speed, frequency, and wavelength. Doubling the tension while maintaining frequency results in a standing wave, but the number of antinodes will change due to the increased speed. Understanding these relationships is essential for predicting wave behavior in strings under varying tension.
nophun6
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Here is my question (2 parts)

a) Draw the standing wave that occurs if the string
tension is quadrupled while the frequency is held
constant.
im not sure how these are related, any equation?

b) Suppose the tension is doubled while the
frequency shaking the string is held constant. Will there be a standing wave? If so how many antinodes will it have?
I know an antinode is an area of maximum amplitude, but not sure if there will be a standing wave, how do i determine this.

thanks.
 
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How is the velocity of propagation of a wave down a string related to the tension in the string?
 
Once you have found the equation berkeman is referring to it is a simple step to go from the velocity to frequency when dealing with wave motion. You just need to relate these two quantities via the amount of nodes and antinodes in the standing wave.

If the tension in the string is increased, that is the string is pulled tighter between the two end points, the speed of propagation of the disturbances (shaking the string at a certain frequency...) will increase. This means that the individual outgoing and reflected pulses will interfere at a lower rate (they will be further apart since they are now traveling faster). The endpoint conditions will stay the same - nodes. It is just that less nodes and antinodes will form between the endpoints since in both cases since the frequency of generation of disturbances in the string is kept constant - that is the phase relationship between the outgoing and reflected pulses are kept the same in time, but in space the meet at a lower rate since they are further apart along the string.
 
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A standing wave will form if the resultant waveform will fit on the string. If the waveform fits at a frequency f_o and the speed of propagation changes then the wavelength needs to change by the same factor since
f_o=\frac{v}{\lambda}
stays constant. If the wavelenght were equal to L before the speed change and then changed to 2.0\ v_o then the wavelength also needs to change by the same factor.
 
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