Standing Wave Wavelengths on 12m Rope: 2m, 1m & 5.5m

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If two wavelengths of standing waves on a 12 meter rope secured at both ends are 2 meters and 1 meter, which of the following could not be a standing wave wavelength on teh same rope with the same tension?


Choices are: 4m, 2.5m, 1.5m, 67cm


12-2 =10, so 1\2 would be 5 and 12-1 = 11, so 1\2 = 5.5. I am rationalizing that 67 cm is not possible.
 
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I don't understand your calculations, and your answer is incorrect. Could you show your reasoning?

In order for there to be a standing wave, the rope's length must be an integer multiple of half a wavelength. If you don't see why, try drawing a diagrams of the first few harmonics, remembering that the ends of the rope must be nodes. So, which of the wavelengths satisfy this requirement?
 
I am still confused. I do not know what numbers to use from the problem into the equation.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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