Standing Wave Wavelengths on 12m Rope: 2m, 1m & 5.5m

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For a standing wave on a 12-meter rope, the wavelengths must be integer multiples of half the rope's length. Given the wavelengths of 2 meters and 1 meter, the possible wavelengths must fit the equation where the rope length is an integer multiple of half a wavelength. The discussion concludes that 67 cm (0.67 m) cannot be a standing wave wavelength, as it does not satisfy the integer multiple condition. Participants express confusion over the calculations and the reasoning behind the standing wave requirements. Understanding the relationship between rope length and wavelength is essential for determining valid standing wave wavelengths.
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If two wavelengths of standing waves on a 12 meter rope secured at both ends are 2 meters and 1 meter, which of the following could not be a standing wave wavelength on teh same rope with the same tension?


Choices are: 4m, 2.5m, 1.5m, 67cm


12-2 =10, so 1\2 would be 5 and 12-1 = 11, so 1\2 = 5.5. I am rationalizing that 67 cm is not possible.
 
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I don't understand your calculations, and your answer is incorrect. Could you show your reasoning?

In order for there to be a standing wave, the rope's length must be an integer multiple of half a wavelength. If you don't see why, try drawing a diagrams of the first few harmonics, remembering that the ends of the rope must be nodes. So, which of the wavelengths satisfy this requirement?
 
I am still confused. I do not know what numbers to use from the problem into the equation.
 
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